Question 3 and 4, Exercise 4.1
Solutions of Question 3 and 4 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.
Question 3
The $n$th term of the sequence is given, find the first 4 terms; the 10th term, $a_{10}$ and the 15 th term: $a_{n}=\frac{n}{n+1}$
Solution.
Given $$a_n = \frac{n}{n+1}.$$ Then
\begin{align*}
a_1 &= \frac{1}{1+1} = \frac{1}{2}\\
a_2 &= \frac{2}{2+1} = \frac{2}{3}\\
a_3 &= \frac{3}{3+1} = \frac{3}{4}\\
a_4 &= \frac{4}{4+1} = \frac{4}{5}\\
\end{align*}
Now
\begin{align*}
a_{10} &= \frac{10}{10+1} = \frac{10}{11}\\
a_{15} &= \frac{15}{15+1} = \frac{15}{16}
\end{align*}
So,
$a_1 = \frac{1}{2},\quad a_2 = \frac{2}{3},\quad a_3 = \frac{3}{4},\quad a_4 = \frac{4}{5},\quad a_{10} = \frac{10}{11},\quad a_{15} = \frac{15}{16}.$ 
Question 4
The $n$th term of the sequence is given, find the first 4 terms; the 10th term, $a_{10}$ and the 15 th term: $a_{15}$.$a_{n}=n^{2}+1$
Solution.
Do yourself.
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