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Question 5, Exercise 2.6

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3}=10$\\ ** Solution. ** The above system may be written as $A X=B$; where, \begin{align*} &A = \begin{bma... {3}=-1$\\ ** Solution. ** The above system maybe written as $AX = B $, where: \begin{align*} &A = \begin{b... _{3}=5$\\ ** Solution. ** The above system maybe written as $AX = B $, where: \begin{align*} &A = \begin{b