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- Question 2, Exercise 2.3 @math-11-nbf:sol:unit02
- t 2) = (1) (4 - 10) = -6 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}... \cdot 3) = (1) (-1) = -1 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}... dot 0) = (1) (1 - 0) = 1 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}... dot 0) = (1) (6 - 0) = 6 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}
- Question 1, Review Exercise @math-11-nbf:sol:unit02
- on\\ * %%(c)%% subtraction\\ * (d) all of these \\ <btn type="link" collapse="a4">See Answer</btn... * %%(c)%% Gauss-Jordan method * (d) all of these \\ <btn type="link" collapse="a10">See Answer</bt... ollapse id="a10" collapsed="true">%%(d)%%: all of these</collapse> ====Go to ==== <text align="right
- Question 9, Exercise 1.4 @math-11-nbf:sol:unit01
- 0>The contents, given in the textbook, related to these question are not suffient to solve such problems.... 0>The contents, given in the textbook, related to these question are not suffient to solve such problems.
- Question 3, Exercise 1.4 @math-11-nbf:sol:unit01
- ft(\dfrac{b}{a}\right). \end{align*} We can write these complex numbers in polar form as: \begin{align*}
- Question 12 and 13, Exercise 6.2 @math-11-nbf:sol:unit06
- tal letters $=5$\\ Total possible arrangements of these $5$ letters $=5!=120$\\ Vowel letters in the give
- Question 14 and 15, Exercise 6.2 @math-11-nbf:sol:unit06
- possibile arrangements. ** Solution. ** To find these arrangement, we treat all books on one subject as
- Question 1(i-v), Exercise 6.3 @math-11-nbf:sol:unit06
- $0<r<n$.\\ Let $X$ be the total combinations. \\ These $r$ objects may be arranged in $r$ ! ways but all
- Question 9 and 10, Exercise 6.3 @math-11-nbf:sol:unit06
- 10$ in ${ }^{10} C_{7}$ ways had after choosing\\ these $7$ girls remaining $3$ girls can be chosen in on