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Question 2, Exercise 2.3

4 Hits, Last modified: 10 months ago

t 2) = (1) (4 - 10) = -6 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}... \cdot 3) = (1) (-1) = -1 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}... dot 0) = (1) (1 - 0) = 1 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}... dot 0) = (1) (6 - 0) = 6 \end{align*} Now, we use these cofactors to find the determinant: \begin{align*}

Question 1, Review Exercise

3 Hits, Last modified: 7 months ago

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