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Question 2, Exercise 2.5
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} \\ 0 & 0 & 1 \end{array} \right] \end{align*} There are $3$ non-zero rows.\\ The rank of the matrix i... nd{array} \right] \quad R3 - 12R2 \\ \end{align*} There are $2$ non-zero rows.\\ The rank of the matrix i... rray} \right] \quad \frac{3}{124}R3 \end{align*} There are $3$ non-zero rows.\\ The rank of the matrix i... \right] \quad R1 - 3R2, \, R3 - 3R2 \end{align*} There are $2$ non-zero rows.\\ The rank of the matrix i
Question 1, Exercise 2.6
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\end{align*} With the different values of $x_3$, there are infinite solutions. Hence solution is; \beg
Question 4, Exercise 2.6
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} R_2 \text{ by 11 and } R_3 - R_2). \end{align*} There is no value of $x$. Then $x_3 = 0$. From the s