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- Exercise 1.2 (Solutions) @fsc-part1-ptb:sol:ch01
- ons) ====== <lead>Notes (Solutions) of Exercise 1.2: Textbook of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Textbook Board (PTB) Lahore.... estion 16(i) ** Separate into real and imaginary parts: $\dfrac{2-7i}{4+5i}$ (write into simple complex number) ... stion 16(ii) ** Separate into real and imaginary parts $\dfrac{{{\left( -2+3i \right)}^{2}}}{\left( 1+i \right)}$ (write into simple complex number) **Solutions** $\dfrac{{{\left( -2+3i \right)}^{2}}}{\left( 1+i \right)}=\dfrac{4+9{
- Exercise 2.8 (Solutions) @fsc-part1-ptb:sol:ch02
- tions) ====== <lead>Notes (Solutions) of Exercise 2.8: Textbook of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Textbook Board (PTB) Lahore.... KISTAN. \\ Page URL: https://www.mathcity.org/fsc-part1-ptb/sol/unit-02/ex2-8 \\ **License:** These resources are shared
- Exercise 1.1 (Solutions) @fsc-part1-ptb:sol:ch01
- lgebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Textbook Board (PTB) Lahore.... begin{array}{|c|c|} \hline + & 1 \\ \hline 1 & 2 \\ \hline \end{array} \] As $1+1=2 \notin \{1\}$. This implies $\{1\}$ does not satisfy closure pr... & -1 \\ \hline 0 & 0 & -1 \\ \hline -1 & -1 & -2 \\ \hline \end{array} \] As $(-1)+(-1)=-2 \notin