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Question 2, Exercise 8.1
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}+1}{2\sqrt{2}}. \end{align*} GOOD **Alternative Method (if $\cos 15^{\circ}$ is not given)** \begin{alig... = \dfrac{\sqrt{3}+1}{2\sqrt{2}}$. **Alternative Method (if $\cos 15^\circ$ is not given)** To find $\co
Question 1, Exercise 8.1
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= -\sqrt{3} \end{align*} GOOD m( **Alternative Method** * $\cos(180+60) = \cos(2(90)+60) = -\cos 60^
Question 8(xiii, xiv & xv) Exercise 8.2
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s\alpha}\\ & = 2 =RHS \end{align*} **Alternative Method** \begin{align*} LHS &= \dfrac{\sin 3 \alpha}{\si
Question 5 and 6, Review Exercise
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lies & \tan \alpha =1 \end{align*} **Alternative Method:**\\ \begin{align*} & \sin (\alpha - \theta)= \co
Question 7, Review Exercise
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lies & \tan \alpha =1 \end{align*} **Alternative Method:**\\ \begin{align*} & \sin (\alpha - \theta)= \co