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- Question 11 Review Exercise 6
- following spinner, determine the probability. ====Solution==== Total number colors $$n(S)=4$$ P(orange) The
- Question 9 & 10 Review Exercise 6
- an be formed with the digits $2,3,0,3,4,2,3$? ====Solution==== We know that $1$ million $=100,0000$. First ... ability that two particular men sit together. ====Solution==== The total number of ways that $n$ persons can
- Question 5 & 6 Review Exercise 6
- wo students refuse to sit next to each other? ====Solution==== The total number of seats are six so $$n=6$$ ... tudents insist on sitting next to each other? ====Solution==== The total number of seats are six so $n=6$. ... aisal and Saima are seated next to each other ====Solution==== The total number of ways sitting of six peopl
- Question 7 & 8 Review Exercise 6
- )=0.5$ and $P(B / A)=0.4$, find $P(A \cap B)$ ====Solution==== We know that: \begin{align} P(B \mid A)&=\dfr... P(B)=0.5$ and $P(B / A)=0.4$, find $P(A / B)$ ====Solution==== We know that $$P(A \mid B)=\dfrac{P(A \cap B)... )=0.5$ and $P(B / A)=0.4$, find $P(A \cup B)$ ====Solution==== \begin{align} P(A \cup B)&=P(A)+P(B)-P(A \cap... ith $35$ and no-digits appear more than once? ====Solution==== If each telephone number starts with $35.$
- Question 2 Review Exercise 6
- ${ }^{2 n} C_r={ }^{2 n} C_{r+2}$; find $r$. ====Solution==== Given that: \begin{align} { }^{2 n} C_r&={ }^... {18} C_r={ }^{18} C_{r+2}$; find ${ }^r C_5$. ====Solution==== Given that: \begin{align} { }^{18} C_r&={ }^{
- Question 3 & 4 Review Exercise 6
- P_{r+6}:{ }^{54} P_{r+3}=30800: 1$. Find $r$. ====Solution==== Given that: \begin{align} { }^{56} P_{r+6}:{ ... y^3 z^5$ can be expressed without exponents? ====Solution==== We can write the word $x^4 y^3 z^5$ as: $$x^4
- Question 10 Exercise 6.5
- that either both are apples or both are good? ====Solution===== Total number of Apples $=20$ number of Orang
- Question 9 Exercise 6.5
- d the probability that both will be selected. ====Solution==== \begin{align} P(\text { Ajmal scicction })&=\... nd the probability that Only one is selected. ====Solution==== \begin{align} P(\text { Ajmal scicction })&=\... d the probability that none will be sclected. ====Solution==== \begin{align} P(\text { Ajmal scicction })&=\... y that at least one of them will be selected. ====Solution==== \begin{align} P(\text { Ajmal scicction })&=\
- Question 8 Exercise 6.5
- y that the sum of digits is neither $7$ nor $11.$ Solution: The sample space rolling a pair of dice is \begi
- Question 7 Exercise 6.5
- that the card drawn is neither red nor king? ====Solution==== A deck of playing cards consists of $52$ card
- Question 5 and 6 Exercise 6.5
- What is the probability of failing the test? ====Solution==== Here we can differentiate as: Let $$E=\{ even... second dice shows a number greater than $4$? ====Solution==== The sample space of throwing the second dice
- Question 3 and 4 Exercise 6.5
- $P(B)$ if $A$ and $B$ are mutually exclusive. ====Solution==== We are given that $\mathrm{A}$ and $B$ are mu... er is either odd or the square of an integer. ====Solution==== Total numbers written on tickets are \begin{a
- Question 1 and 2 Exercise 6.5
- \cup B)=\dfrac{1}{2}$.\\ Find $P(A \cap B)$. ====Solution==== We know by addition law of probability \begin... P(A \cup B)=\dfrac{3}{4}$. Find $P(A \cap B)$ ====Solution==== We are given: $$P(A)=\dfrac{1}{2}, P(\bar{B})... dfrac{3}{4}$. Find $P(\bar{A} \cap \bar{B})$. ====Solution==== We are given: $$P(A)=\dfrac{1}{2}, P(\bar{B})
- Question 7 Exercise 6.4
- obability of getting doublet of even numbers. ====Solution==== The sample space rolling a pair of dice is \b... probability of getting a sum less than $6$. ====Solution==== The sample space rolling a pair of dice is \b... e probability of getting a sum more than $7.$ ====Solution==== The sample space rolling a pair of dice is \b... bability of getting a sum greater than $10.$ ====Solution==== The sample space rolling a pair of dice is \b
- Question 6 Exercise 6.4
- obability of each of the Drawing an ace card. ====Solution==== Total cards $$=52$$ An ace. Total ace cards $... f each of the Drawing either spade or hearıs. ====Solution==== Total cards $=52$ Drawing either space or he... bility of each of the Drawing a diamond card. ====Solution==== Total cards $=52$ Drawing a diamond card. T... obability of each of the Drawing a face card. ====Solution==== Total cards $=52$(iv) Drawing a face card. T