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- Question 14 Exercise 7.1
- $2^{2 n}-1$ is a multiple of $3$ for all natural numbers. ====Solution==== 1. For $n=1$ then $$2^{2 n}-1=2
- Question 1 Review Exercise 7
- ): $2520$</collapse> ii. How many two digits odd numbers can be formed form the digits $\{1,2,3,4,5,6,7\}$