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- Question 15 & 16 Exercise 4.5
- xt{Rs.}= 1073741823$$ =====Question 16===== The number of bacteria in a culture increased geometrically ... e is assumed to be constant. ====Solution==== The number of bacteria at the start $a_1=64000$ Let number of bacteria after first day be $a_2$, after second be $a_3$ and so on. The number of bacteria after $6$th day $a_7=729000$. Since t
- Question 1 Exercise 4.3
- ==== Find indicated term and sum of the indicated number of terms in arithmetic sequence: $9,7,5,3, \ldots... ==== Find indicated term and sum of the indicated number of terms in case of arithmetic sequence: $3, \dfr
- Question 13 & 14 Exercise 4.3
- heater? ====Solution==== \begin{align}\text{Total number of rows}& n=40,\\ \text{Seats in a first row} a_1... n arithmetic equence.\\ We have to find the total number of seats that are $S_{40}$.\\ We know by sum form
- Question 3 and 4 Exercise 4.2
- }{3} \\ \implies &n=24+1=25.\end{align} Thus, the number of terms in given progression are $25$. GOOD ===
- Question 5 and 6 Exercise 4.2
- term. Each term of the sequence is $\log$ of some number. Each log contains $a$ but the power of $b$ in fi
- Question 11 Exercise 4.2
- n=5400$, we have to find $n$, which represent the number of hours to reach at top. We know \begin{align}
- Question 9 & 10 Exercise 4.3
- (315-306) = 9 \text { and } a_n=693 .$$\\ Let the number of terms be $n$. Then\\ \begin{align}a_n&=a_1+(n-
- Question 4 & 5 Exercise 4.4
- &=10 \text { or } n=11\end{align} Hence the total number of terms are $11$ in sequence.\\ =====Question 5
- Question 7 & 8 Exercise 4.5
- 728$; find them. =====Solution===== Let the three number are $\dfrac{a}{r}, a . a r$ \\ then by the given