Search

Fulltext results:

Exercise 2.1 (Solutions)

5 Hits, Last modified: 3 years ago

, Theorem)$$ $$(m \overline{OB})^2 = 4 + 1 = 5 $$ therefore $$m \overline{OB} = \sqrt{5}$$ thus $$m \ove... The mean of the numbers is between given numbers. Therefore $\frac{3/4+5/9}{2}= \frac{47}{72}$ is a numbe... 2)$$ Subtract (1) from (2), we get $$9x = 5$$ $$\therefore \,\, x = \frac{5}{9}$$ $$0.\overline{5} = \f... qquad (2)$$ Subtract (1) from (2) $$99x = 13$$ $$\therefore \,\, x = \frac{13}{99}$$ $$0.\overline{13} =

Exercise 2.5 (Solutions)

2 Hits, Last modified: 3 years ago

imaginary parts} \\ iy = -3i\\ \therefore y = -3\\ x + 1 = 4\\ x = 4 - 1\\ \therefore x = 3 \end{array}$$