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- MCQs with Answers (FSc/ICS Part 1) @fsc:fsc_part_1_mcqs
- MCQs of all chapters of FSc/ICS Part1 are given. There are seven chapters. Answers of MCQs is starting f
- FSc/ICS Part 2 Solutions @fsc
- r HSSC-II), Punjab Text Book Board Lahore.</lead> There are seven units in this book and we have work har... l License or stated otherwise. To view PDF files, there must be PDF Reader (Viewer) installed on your PC
- FSc/ICS Part 2 (Mathematics): PTB
- I), Punjab Textbook Board (PTB) Lahore, Pakistan. There are total seven (7) units in this book.</lead> O
- Definitions: FSc Part 1 (Mathematics): PTB by Aurang Zaib @fsc-part1-ptb
- rt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \). Therefore, \( |z| = 5 \). =====Chapter 02: Set and Oper... well-defined. ====Methods to describe a set==== There are 3 method to describe a set ====Descriptive Me... ====Equivalent Set==== Two sets are equivalent if there exists a one-to-one correspondence between their ... forms a group because for every integer \( a \), there exists its additive inverse \( -a \), and additio
- Definitions: FSc Part 1 (Mathematics): PTB @fsc-part1-ptb
- ct collection of distinct object is called set.\\ There are three ways to describe a set.\\ * **Descri... two numbers $a$ and $b$. If $a,G,b$ are in $G.P$. Therefore $\frac{G}{a}=\frac{b}{G} \longrightarrow G^2... 1}{5},\frac{1}{7}$ are in harmonic sequence since there reciprocals $1,3,5,7$ are in $A.P$. * **Harmon
- MathCraft: PDF to LaTeX file: Sample-01 @mathcraft
- hi$ is continuous for all $r \in \mathbb{R}$. And therefore $\log$-convex. We need following lemma which
- Topology and Functional Analysis Solved Paper by Noman Khalid @notes
- s-solved-pu-a2011.pdf}} </modal> </callout> ====There are other notes on the toplogy subject==== {{topi
- Question 17 Exercise 4.2 @math-11-kpk:sol:unit04
- KPTBB) Peshawar, Pakistan. =====Question 17===== There are $n$ arithmetic means between 5 and 32 such th
- Question 8 Exercise 4.2 @math-11-kpk:sol:unit04
- dfrac{a+b-c}{c}$ are in A.P, thus\\ \begin{align}\therefore \dfrac{c+a-b}{b}-\dfrac{b+c-a}{a}&=\dfrac{a+b
- Question 5 and 6 Exercise 4.2 @math-11-kpk:sol:unit04
- , in second term the power of $b$ is 1 and so on, therefore $$a_n=\log (a b^{n-1}).$$ We show that the g
- Formatting Syntax @wiki
- es_do_not_work|Mozilla Knowledge Base]]. However, there will still be a JavaScript warning about trying t... be added to the [[doku>entities|pattern file]]. There are three exceptions which do not come from that ... xbasic xml xojo xorg_conf xpp yaml z80 zxbasic// There are additional [[doku>syntax_highlighting|advance
- Question 5 and 6 Exercise 7.3 @math-11-kpk:sol:unit07
- ht) \\ & \times\left(1+\frac{5 x}{8}\right) \\ & \therefore\left(1-\frac{5 x}{4}\right)\left(1+\frac{5 x}
- Question 8 Exercise 7.2 @math-11-kpk:sol:unit07
- here } \\ & x^2=\frac{3}{2} \frac{3}{2}: 8 \\ & \therefore \frac{11}{1} \cdot i \quad 7 \\ & =5.82 \quad
- Question 6 Exercise 7.2 @math-11-kpk:sol:unit07
- cause $r$ should be a positive integer. It means there is no constant term or term independent of $x$ in
- Solutions: Math 11 KPK @math-11-kpk
- s in accordance with this plan (SLOs based). But there is no doubt that these solutions are valid for al