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Question 2, Exercise 1.3

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$$p\left( z \right)={{z}^{3}}+6z+20$$ By factor theorem, $(z-a)$ is a factor of $P(z)$ iff $P(a)=0$. Put ... z \right)={{z}^{3}}-2{{z}^{2}}+z-2$$ \\ By factor theorem $(z-a)$ is a factor of $()$ iff $P(a)=0$.\\ Put $