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Question 16 & 17, Exercise 2.2

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4 & 2 \\ \end{matrix} \right]$$ $$|A|=6+4$$ $$\Rightarrow |A|=10\ldots (1)$$ $$A^{-1}=\dfrac{1}{|A|}AdjA$$ ... & 11 \\ -1 & 1 \\ \end{matrix} \right]$$ $$\Rightarrow |AB|=4+11$$ $$\Rightarrow \,\,|AB|=15$$ $$AdjAB=\left[ \begin{matrix} 1 & -11 \\ 1 & 4 \\ \end{matrix... & -11 \\ 1 & 4 \\ \end{matrix} \right]$$ $$\Rightarrow ( AB )^{-1}=\left[ \begin{matrix} \dfrac{1}{15

Question 12, Exercise 2.2

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\lambda (1-(\lambda ^2-1))$$ $A$ is singular. $$\Rightarrow |A|=0$$ $$\lambda (1-(\lambda ^2-1))=0$$ $$\lamb