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- Exercise 2.6 (Solutions)
- ac{\overline{z}}{\overline{w}}$ * (v) $\frac{1}{2}(z+\overline{z})$ is real part of z * (vi) $\frac{1}{2i}(z-\overline{z})$ is ... &= \frac{1}{2}(4)\\ &= 2 \hbox{ (it is real part of } z). \end{array}$$ 6(vi) $$\begin{array}{cl} \frac{1}{2i}(z-\overline{z}) &= \frac{1}{2}(2+3i-(2-3i))\\ &= \frac{1}{2}(2+3i-2+3i)\\
- Exercise 2.5 (Solutions)
- =======Exercise 2.5 (Solutions)======== ====Question 1==== * Evaluate (i) $i^7$ ... (ii) $i^{50}$ (iii) $i^{12}$ ... t)^5$ (vi) $i^{27}$ **Solution**\\ (i) $$\begin{array}{cl} i^7 &= {i^6}\cdot i\\ &= (i^2)^3\cdot i\\ &= {-1}^3 \cdot i\\ &= -i \end{