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Exercise 2.6 (Solutions)
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\\ (ii) $i^{73}=-i$\\ (iii) $i^{10} = -1$\\ (iv) Complex conjugate of $(-6i + i^2) is (-1 + 6i)$\\ (v) Difference of complex numbers $z = a + ib$ and its conjugate is a real ... = 5+8i$, then a = 6 & b = -11\\ (vii) Product of complex number and its conjugate is always a non-negative... True (vii) True ====Question 2==== Express each complex number in the standrad form $a+ib$, where a and b