<?xml version="1.0" encoding="UTF-8"?>
<!-- generator="FeedCreator 1.8" -->
<?xml-stylesheet href="https://www.mathcity.org/lib/exe/css.php?s=feed" type="text/css"?>
<rss version="2.0">
    <channel xmlns:g="http://base.google.com/ns/1.0">
        <title>MathCity.org</title>
        <description>Merging man &amp; maths</description>
        <link>https://www.mathcity.org/</link>
        <lastBuildDate>Thu, 04 Jun 2026 21:18:39 +0000</lastBuildDate>
        <generator>FeedCreator 1.8</generator>
        <image>
            <url>https://www.mathcity.org/_media/logo.svg</url>
            <title>MathCity.org</title>
            <link>https://www.mathcity.org/</link>
        </image>
        <item>
            <title>Question 9 &amp; 10 Exercise 4.3</title>
            <link>https://www.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p6</link>
            <description>Question 9 &amp; 10 Exercise 4.3

Solutions of Question 9 &amp; 10 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$$306,315,324,333, \ldots, 693$$$a=306$$$d=(315-306) = 9 \text { and } a_n=693 .$$$n$\begin{align}a_n&amp;=a_1+(n-1) d \text { becomes } \\
\Rightarrow a_1+(n-1) d&amp;=693 \\
\Rightarrow 306+(n-1) \cdot 9&amp;=693 \\
\Rightarrow 9 n&amp;=396 \\
\Rightarr…</description>
            <author>anonymous@undisclosed.example.com (Anonymous)</author>
            <pubDate>Fri, 05 Jan 2024 17:29:57 +0000</pubDate>
        </item>
    </channel>
</rss>
