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        <description>Merging man &amp; maths</description>
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        <item>
            <title>Question 7(i-vi), Exercise 6.1</title>
            <link>https://www.mathcity.org/math-11-nbf/sol/unit06/ex6-1-p7</link>
            <description>Question 7(i-vi), Exercise 6.1

Solutions of Question 7(i-vi) of Exercise 6.1 of Unit 06: Permutation and Combination. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$\quad \dfrac{n!}{(n-2)!}=930,\quad n \geq 2$\begin{align*}
\dfrac{n!}{(n-2)!}&amp;=930\\
\dfrac{n(n-1)(n-2)!}{(n-2)!}&amp;=930\\
n(n-1)&amp;=930\\
n^2-n-930&amp;=0
\end{align*}\begin{align*}
n&amp;=\dfrac{1\pm \sqrt{1+4(930)}}{2}\\
&amp;=\dfrac{1\pm …</description>
            <author>anonymous@undisclosed.example.com (Anonymous)</author>
            <pubDate>Sat, 08 Mar 2025 08:59:37 +0000</pubDate>
        </item>
        <item>
            <title>Question 7(vii-xi), Exercise 6.1</title>
            <link>https://www.mathcity.org/math-11-nbf/sol/unit06/ex6-1-p8</link>
            <description>Question 7(vii-xi), Exercise 6.1

Solutions of Question 7(vii-xi) of Exercise 6.1 of Unit 06: Permutation and Combination. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$\quad n!=990 \cdot (n-3)!$\begin{align*}
n!&amp;=990  (n-3)!\\
n(n-1)(n-1)(n-3)!&amp;=990  (n-3)!\\
n(n-1)(n-1)&amp;=990 \\
n^3-3n^2+2n-990 &amp;=0\\
\end{align*}\[\begin{array}{c|cccc}
 &amp; 1 &amp; -3 &amp; 2 &amp; -990 \\  
11 &amp; 0  &amp; 11 &amp; 88 &amp; 990 \\…</description>
            <author>anonymous@undisclosed.example.com (Anonymous)</author>
            <pubDate>Sat, 08 Mar 2025 08:59:36 +0000</pubDate>
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        <item>
            <title>Question 1(vi-x), Exercise 6.3</title>
            <link>https://www.mathcity.org/math-11-nbf/sol/unit06/ex6-3-p2</link>
            <description>Question 1(vi-x), Exercise 6.3

Solutions of Question 1(vi-x) of Exercise 6.3 of Unit 06: Permutation and Combination. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n\in N$$\quad^{2n}C_n=\dfrac{2^n[1.3.5.\cdots(2n-1)]}{n!}$\begin{align*}L.H.S &amp;=\quad^{2n}C_n \\
&amp;=\dfrac{(2 n)!}{n!(2 n-n)!}\\
&amp;=\dfrac{(2 n)(2 n-1)(2 n-2)(2 n-n)(2 n-(n+1)) ..2 .1}{n!\cdot n!}\\
&amp;=\dfrac{(2 n)(2 n-1)(2 n-2) ..(…</description>
            <author>anonymous@undisclosed.example.com (Anonymous)</author>
            <pubDate>Sat, 08 Mar 2025 09:00:26 +0000</pubDate>
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